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Q.

The entropy (S°) of the following substances are : 
CH4(g) = 186.2JK1mol1O2(g)   = 205.0JK1mol1 CO2(g)=213.6JK1mol1H2O(l) =69.9JK1mol1
The entropy change (S°) for the reactionCH4(g)+2O2(g)CO2(g)+2H2O(l) is

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a

312.5JK1mol1

b

242.8JK1mol1

c

108.1JK1mol1

d

37.6JK1mol1

answer is B.

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Detailed Solution

ΔS=ΔSproducts ΔSreactants  =CO2+2H2OCH4+2O2 =353.4-596.2 = - 242.8

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The entropy (S°) of the following substances are : CH4(g) = 186.2JK−1mol−1O2(g)   = 205.0JK−1mol−1 CO2(g)=213.6JK−1mol−1H2O(l) =69.9JK−1mol−1The entropy change (∆S°) for the reactionCH4(g)+2O2(g)→CO2(g)+2H2O(l) is: