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The entropy $(S^{0})$ values methane,oxygen, carbon dioxide and water are 186.2, 205, 213.6 and 69.9 $J . K^{- 1} {mol}^{- 1}$ respectively. The entropy change $(∆ S^{0})$ for the reaction, ${CH}_{4} (g) + 2 O_{2} (g) \to {CO}_{2} (g) + 2 H_{2} O (g)$ will be

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$- 312.5 {JK}^{- 1} {mol}^{- 1}$

$- 242.8 {Jk}^{- 1} {mol}^{- 1}$

$- 108.1 {Jk}^{- 1} {mol}^{- 1}$

$- 37.6 {Jk}^{- 1} {mol}^{- 1}$

answer is B.

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Detailed Solution

$∆ S = \underset{}{\sum S_{products} - \sum_{} S_{reactnts} = (213.6 + 2 \times 69.9) - (186.2 + 2 \times 205)} = - 242.8$

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