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The equation whose roots are 2 times to the roots of $x^{4} + 2 x - 3 = 0$ is

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$x^{4} + 4 x - 12 = 0$

$x^{4} + 16 x + 96 = 0$

$x^{4} - 16 x + 48 = 0$

$x^{4} + 16 x - 48 = 0$

answer is B.

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Detailed Solution

$f (\frac{x}{2}) = 0$ $\Rightarrow {(\frac{x}{2})}^{4} + 2 (\frac{x}{2}) - 3 = 0$

$\Rightarrow x^{4} + 16 x - 48 = 0$

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