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Q.

The equation  2cos2(x2)sin2x=x2+1x2, 0≤x≤π2has

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a

No solution

b

More than one real solution

c

None of these

d

One real solution

answer is A.

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Detailed Solution

2cos2(x2)sin2x=x2+1x2

2cos2x2sin2x=2

No 'x'satisfies the given interval  (0≤x≤π2)

[∴x2+1x2≥2]

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