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Q.

The equation for the displacement of a particle executing SHM is y = {5 sin 2π t} cm. Find (i) the velocity at 3cm from the mean position, (ii) acceleration after 0.5s after leaving the mean position.

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a

8πcms−1, zero 

b

2πcms−1, zero 

c

6πcms−1, zero 

d

4πcms−1, zero 

answer is A.

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Detailed Solution

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y=5sin⁡ 2πtA=5 cm ω=2π⇒T=1 sec y=3 cmv=ωA2−y2=2πT25−9v=2π×4=8πcm/seca=ω2y⇒ after 0.5sec it is at mean position ⇒y=0 a=0

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