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Q.

The equation motion of a particle in S.H.M is large a + 16{pi ^2}x, = ,0. In the equation ‘a’ is the linear acceleration (in m/sec2) of the particle at a displacement ‘x’ in meter. The time period  of S H M in seconds is

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a

 

14

b

12

c

1

d

2

answer is B.

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Detailed Solution

large a + 16{pi ^2}x, = ,0

But S.H.M equation is  large a, = , - {omega ^2}x, Rightarrow ,{omega ^2}, = ,16{pi ^2}

large Rightarrow ,w, = ,4pi , Rightarrow ,frac{{2pi }}{T}, = ,4pi , Rightarrow ,T, = ,frac{2}{4}, = ,frac{1}{2}sec

 

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