Q.

The equation of a line having intercepts a,b  on the axes such that a+b=5,ab=6  is

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By Expert Faculty of Sri Chaitanya

a

2x+3y6=0

b

3x+2y6=0

c

2x+10y5=0

d

10x+2y5=0

answer is B, D.

(Detailed Solution Below)

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Detailed Solution

a+b=5,ab=6

(ab)2=(a+b)24ab(ab)2=(5)24×6ab=1

By simplifying a+b=5 ,ab=1   a=3,b=2

Equation of the line is x3+y2=12x+3y6=0  (when a  is x-intercept, b  is y-intercept)

x2+y3=13x+2y6=0     (whena is y-intercept, b  is x-intercept)

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