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Q.

The equation of a parabola is 25(x2)2+(y+5)2=(3x+4y1)2 For this parabola

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a

tangent at the vertex is 6x + 8y + 13 = 0

b

focus = (2, –5)

c

axis has the equation 4x –3y –23 = 0

d

directrix has the equation 3x + 4y +1 = 0

answer is A, B, C, D.

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Detailed Solution

EQ of parabola is 
(x2)2+(y+5)2=3x+4y132+422
Focus = S(2, – 5)
Equation of directrix is 3x + 4y – 1 = 0;
Eq. of axis is 4x – 3y – 23=0 Eq. of L.R is
 3x + 4y + 14 = 0
Eq. of tangent at vertex is 3x+4y+1412=06x+8y+13=0

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