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Q.

The equation of a particle executing simple harmonic motion is given by x=sinπ t+ 1 3 m   At t = 1s, the speed of particle will be (Given : π=3.14   )


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a

0 cm s −1  

b

157  cm s −1  

c

272 cm s −1  

d

314 cm s −1   

answer is B.

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Detailed Solution

x=sinπ t+ 1 3 ⇒ϑ= cosπ t+ 1 3 π  
 At t=1s⇒ϑ=−πcosπ 1+ 1 3 =πcos 4 π 3  
=3.14× 1 2 =1.57m/s=157cm/s  
 
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