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The equation of a stationary wave is $y = 4 \sin (\frac{π x}{5}) \cos (100 π t) c m .$ The wave is formed using a string of length 20 cm. The second and 3^rd antinodes are located at positions (in cm) ........., ...........

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7.5, 12.5

2.5, 7.5

12.5, 17.5

5, 10

answer is A.

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Detailed Solution

$\begin{array}{l} A n t i n o d e = \max a m p h l i t u d e \\ \sin (\frac{π x}{5}) = 1; s l o v e f o r' x' \end{array}$

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