The equation of a tangent to the parabola y² = 8x is y = x + 2. The point on this line from which the other tangent to the parabola is perpedicular to the given tangent is

$\begin{array}{l}{\mathrm{y}}^2=8\mathrm{x}\Rightarrow \mathrm{a}=2\\ Equation of \tan gent is y=mx+\frac{2}{m}\\ Given \tan gent is y=x+2\to \left(1\right)\\ We know that point of intersection of perpendicular \tan gents lies on directrix\\ directrix equation is x=-2\\ sub x=-2 in \left(1\right) then y=0\\ Req.point=(-2,0)\end{array}$