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The equation of a transverse wave propagating in a string is given by $y = 0.02 \sin (x + 30 t)$ Where, x and y are in metre and t is in second. If linear density of the string is $1.3 \times 10^{- 4} k g / m$ , then the tension in the string is

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$0.12 N$

$120 N$

$12 N$

$1.2 N$

answer is A.

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Detailed Solution

$v = \frac{ω}{k} = \sqrt{\frac{T}{μ}} ∴ T = μ {(\frac{ω}{k})}^{2} = (1.3 \times 10^{- 4}) {(\frac{30}{1})}^{2} = 0.12 N$

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