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Q.

The equation of a transverse wave travelling on a rope is given by y = 10 sin π(0.01x - 2.00t) where y and x are in centimetres and t in seconds. The maximum transverse speed of a particle in the rope is about

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a

121 cm/s

b

63 cm/s 

c

10 cm/s 

d

75 cm/s 

answer is A.

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Detailed Solution

Standard equation of travelling wave y = A sin(kx - ωt)  
 By comparing with the given equation
  y = 10 sin(0.01 πx - 2πt)
  A = 10 cm, ω = 2π
 Maximum particle velocity = Aω = 2π  × 10 = 63 cm/s
 

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