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Q.

The equation of a transverse wave travelling on a rope is given by  y=10sinπ(0.01x2.00t)where y and x are in cm and t in seconds. The maximum transverse speed of a particle in the rope is about

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a

62.8 cm/s

b

121 cm/s

c

100 cm/s

d

75 cm/s

answer is A.

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Detailed Solution

detailed_solution_thumbnail

Maximum speed of a particle is given as 

Vmax=

Where A=10cm & ω=2πrad/s for the given wave.

Vmax=10×2π=62.8cm/s

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