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The equation of a transverse wave travelling on a rope is given by y = 10sin $π$ (0.01x–2.00t) where y and x are in cm and t in seconds. The maximum transverse speed of a particle in the rope is about

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62.8 cm/s

75 cm/s

100 cm/s

121 cm/s

answer is A.

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Detailed Solution

y = 10sin $π$ (0.01x - 2.00t)
Comparing y A sin(kx - wt) ; w = $π$ x 2 ; A = 10
V_max =10 x 2 $π$ =10 x 2 x 3.14 = 62.8 cm / s

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