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The equation of a wave is given by (all quantity expressed in S.I. units) $Y = 5 \sin 10 π (t - 0.01 x)$ along the x-axis. The magnitude of phase difference between the points separated by a distance of 10 m along x- axis is

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$π / 2$

$π$

$2 π$

answer is B.

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Detailed Solution

The magnitude of phase difference between the points
separated by distance 10 metres
$= k×10 = [10 π × 0.] ×10= π$

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