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The equation of a wave on a string of linear mass density 0.04 kg m^-1 is given by $y = 0.02 (m) \sin [2 π (\frac{t}{0.04 (s)} - \frac{x}{0.50 (m)})]$ . The tension in the string is

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12.5 N

6.25 N

0.5 N

4.0 N

answer is D.

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Detailed Solution

$T = {μv}^{2} = μ \frac{ω^{2}}{k^{2}} = 0.04 \frac{(2 π / 0.04)^{2}}{(2 π / 0.50)^{2}} = 6.25 N$

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