The equation of a wave on string of linear mass density $0.04kg/m$  is given by $y=0.02\sin \left[2\pi \left(\frac{t}{0.04}-\frac{x}{0.50}\right)\right]$. The tension in the string is

$$\begin{gathered} We know that velocity of wave on the string is v, from the given equation velocty of the wave is v=\frac{\omega }{\kappa } \\ on string \\ V=\sqrt{\frac{T}{\mu }} \\ \Rightarrow V^2=\frac{T}{\mu } \\ \Rightarrow T=\mu .v^2 \\ \Rightarrow T=\mu \frac{w^2}{k^2} \\ \Rightarrow T=0.04\times {\left(\frac{0.50}{0.04}\right)}^2 = 6.25 N \end{gathered}$$