Q.

The equation of a wave pulse is given as y=0.8(4x+5t)+4, the amplitude and velocity of the pulse are

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a

0.2 units, 1.25 units along + ve x-axis

b

0.2 units, 1.25 units along –ve x-axis

c

0.4 units, 1.25 units along –ve x-axis

d

0.4 units, 1.25 units along +ve x-axis

answer is A.

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Detailed Solution

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At amplitude, displacement is maximum,

i.e x = 0 & t = 0.

For same displacement,

4x+5t+4=constant

  ⇒4dx+5dt =0

v=dxdt=-54= -1.25 units

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