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Q.

The equation of circle whose centre lies on $3 x - y - 4 = 0$ and $x + 3 y + 2 = 0$ and has an area of 154 square units is

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a

$x^{2} + y^{2} - 2 x + 2 y - 47 = 0$

b

$x^{2} + y^{2} - 2 x + 2 y + 47 = 0$

c

$x^{2} + y^{2} + 2 x - 2 y - 47 = 0$

d

$x^{2} + y^{2} + 2 x - 2 y + 47 = 0$

answer is A.

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Detailed Solution

Find centre $π r^{2} = 154$ find r

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The equation of circle whose centre lies on 3x−y−4=0 and x+3y+2=0and has an area of 154 square units is