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The equation of hyperbola with coordinate axes as principal axes, distance of one of its vertices from foci is 9 and 1 units is $\frac{x^{2}}{a^{2}} - \frac{y^{2}}{b^{2}} = 1$ then $a + b^{2} =$ ……..

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Detailed Solution

Given ${SA}^{'} = 9, SA = 1, ae + a = 9, a (e - 1) = 1$

$\Rightarrow e = \frac{5}{4}, a = 4, b^{2} = 9$

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