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Q.

The equation of lowest degree with rational coefficients having a root 5+2i  is

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a

x42x2+81=0

b

x46x2+49=0

c

x4+2x2+81=0

d

x4+6x2+49=0

answer is B.

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Detailed Solution

α=5+2i  ,  β=52i

γ=5+2i,δ=52i

(x2x(α+β)+αβ)(x2x(γ+δ)+γδ)=0(x2x(25)+7)(x2+25x+7)=0(x2+7)2(x25)2=0x46x2+49=0

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