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Q.

The equation of motion of a particle of mass 1g is $\frac{d^{2} x}{d t^{2}} + π^{2} x = 0$ where x is displacement (in m) from mean positon. The frequency of oscilation is (in Hz)

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a

2

b

$5 \sqrt{10}$

c

$\frac{1}{5 \sqrt{10}}$

d

$\frac{1}{2}$

answer is A.

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Detailed Solution

$\frac{d^{2} x}{d t^{2}} + π^{2} x = 0$

$a + ω^{2} x = 0$

$ω = π = 2 π n$

$n = \frac{1}{2}$

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The equation of motion of a particle of mass 1g is d2xdt2+π2x=0 where x is displacement (in m) from mean positon. The frequency of oscilation is (in Hz)