The equation of motion of particle is described in column-I. At t=0 Particle is at origin and at rest
Column-I Column-I
a)x=3t² +2t P) Velocity of particle t=1sec is 8m/s
b)V=8t Q) Particle moves with uniform acceleration
c)a=16t R) Particle moves with variable acceleration
d)V=6t-3t² S) Acceleration of the particle at t=1s is 2 m/s²
T) Particle will change its direction of motion

see full answer

21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!

An Intiative by Sri Chaitanya

$A - P Q, B - P R, C - P R, D - R T$

$A - P Q, B - P Q, C - P R, D - R T$

$A - R T, B - P Q, C - P R, D - R T$

$A - P R, B - R T, C - P R, D - P Q$

answer is B.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

A) $x = 3 t^{2} + 2 t, v = 6 t + 2$

$t = 1, v = 8 m / s$

$a = \frac{d v}{d t} = 6 m / s^{2}$

B) $v = 8 t$ t=1 v=8m/s

$a = \frac{d v}{d t} = 8 m / s^{2}$

$C) a = \frac{d v}{d t} = 16 t$

$d v = (16 t) d t$

$\int d v = \int 16 t d t$

$v = \frac{16 t^{2}}{2} = 8 t^{2}$

t=1 v= 8m/s

$D) v = 6 t - 3 t^{2}, a = \frac{d v}{d t} = 6 - 6 t$

Watch 3-min video & get full concept clarity

Column-I	Column-I
a)x=3t² +2t	P) Velocity of particle t=1sec is 8m/s
b)V=8t	Q) Particle moves with uniform acceleration
c)a=16t	R) Particle moves with variable acceleration
d)V=6t-3t²	S) Acceleration of the particle at t=1s is 2 m/s²
	T) Particle will change its direction of motion