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The equation of radical axis of circles $x^{2} + y^{2} + 4 x + 6 y + 7 = 0$ and $4 x^{2} + 4 y^{2} + 8 x + 12 y - 9 = 0$ is

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$x + y + 1 = 0$

$8 x + 12 y = 0$

$8 x + 12 y + 37 = 0$

$2 x + 3 y + 7 = 0$

answer is C.

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Detailed Solution

Given circles are $4 x^{2} + 4 y^{2} + 16 x + 24 y + 28 = 0$ and $4 x^{2} + 4 y^{2} + 8 x + 12 y - 9 = 0$ .

Equation of radical axis is $8 x + 12 y + 37 = 0$ .

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