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Q.

The equation of sides of a triangle are 7x-5y-11=0, 8x+3y+31=0, x+8y-19=0. Then the point (0,0) lies

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a

inside of triangle 

b

outside of triangle

c

on the triangle 

d

can't say

answer is A.

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Detailed Solution

We check the sign of each line when we substitute (0,0). If the signs do not match the triangle's orientation, the point lies outside.

Given side equations

7x - 5y - 11 = 0

8x + 3y + 31 = 0

x + 8y - 19 = 0      

Step 1 - Substitute the point (0,0)

LineExpression value at (0,0)Sign
7x - 5y - 11-11Negative
8x + 3y + 3131Positive
x + 8y - 19-19Negative

Step 2 - Interpret the signs

For a point to be inside a triangle, its sign (positive or negative) when substituted into each side's equation must match the sign of the triangle region for that side. Here, the signs are negative, positive, negative — they are not all the same or consistent with one orientation.

Conclusion

Therefore, the point (0,0) lies outside the triangle.

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