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Q.

The equation of the asymptotes of the hyperbola 2x2+5xy+2y211x7y4=0 is

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a

2x2+4xy+2y27x11y+5=0

b

2x2+5xy+2y2=0

c

2x2+5xy+2y211x7y5=0

d

2x2+5xy+2y211x7y+5=0

answer is C.

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Detailed Solution

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The equation of hyperbola is 2x2+5xy+2y211x7y4=0......1

Let asymptotes of the hyperbola (1) be 2x2+5xy+2y211x7y+c=0......2

Since, Eq (2) represent pair of lines

25/211/25/227/211/27/2c=0

112354+11+727+554+c4254=0

94c=998+1898=908c=5

 equation of the required asymptotes is

2x2+5xy+2y211x7y+5=0

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