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The equation of the circle with centre $(0, 2)$ and radius 2 is $x^{2} + y^{2} - m y = 0$ . The value of m is

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answer is C.

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Detailed Solution

Here $h = 0, k = 2$ and $r = 2$ . Therefore, the required equation of the circle is

$(x - 0)^{2} + (y - 2)^{2} = (2)^{2}$

or $x^{2} + y^{2} - 4 y + 4 = 4$

or $x^{2} + y^{2} - 4 y = 0$

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