The equation of the line parallel to  $3x+5y+7=0$ and passing through  $(–1,2)$ is

Equation of line parallel to  $3x+5y+7=0$ is

$3x+5y+k=0$

But this line passing through  $(-1,2)$

$3(-1)+5\left(2\right)+k=0$

$k=-7$

$\therefore$  equation of line is  $3x+5y-7=0$