The equation of the line passing through $(-2,3)$ and having intercepts equal in magnitude but opposite in sign is

The equation of the line $\Rightarrow \frac{x}{a}+\frac{y}{b}=1$

Given that $a=-b$

$\Rightarrow \frac{x}{-b}+\frac{y}{b}=1$

$\Rightarrow \frac{-x+y}{b}=1$

$\Rightarrow -x+y=b\to \left(1\right)$

Equation (1) passes through $(-2,3)$

$\Rightarrow 2+3=b\Rightarrow b=5$ 

Substitute in equation(1)

$\therefore$ The required line is $\Rightarrow -x+y=5$

$\Rightarrow x-y+5=0$