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Q.

The equation of the plane containing the points (1, 0, 0), (0, 2, 0) and (0, 0, 3) is given by:

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a

x+2y+3z=1

b

3x+2y+z=2

c

6x+3y+2z=6

d

6x+3y+2z=8

answer is C.

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Detailed Solution

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Equation of plane passing through three points

x1,y1,z1,x2,y2,z2 and x3,y3,z3 is given by

xyz1x1y1z11x2y2z21x3y2z31=0

x    y    z    11    0    0    10    2    0    10    0    3    1=0

Expanding this determinant we get

x0    0    12    0    10    3    1y1    0    10    0    10    3    1+z1010210011

1    0    00    2    00    0    3=0

x[1(60)]y[1(03)]+z[1(20)]1[(60)]=06x+3y+2z6=0

6x+3y+2z=6

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