Here, the required plane is a (x - 4) + b (y- 3) + c (z -2) = 0 

Also a+b+2c -0 and a-4b +5c-0 Solving, we have

$\begin{array}{l}\frac{\mathrm{a}}{5+8}=\frac{\mathrm{b}}{2-5}=\frac{\mathrm{c}}{-4-1}=\mathrm{k}\\ \frac{\mathrm{a}}{13}=\frac{\mathrm{b}}{-3}=\frac{\mathrm{c}}{-5}=\mathrm{k}\end{array}$

Therefore, the required equation of plane is    -13x+3y+5z+33=0