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Q.

The equation of the plane passing through the point (0, 1, -4) and normal to the line joining the points(0,–2, 2) and (–3, 1, –2) is ax + by + cz + d= 0 then

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a

a > b > c > d

b

d > c > a > b

c

a > c > d > b

d

c > d > b > a

answer is B.

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Detailed Solution

P(0,1,-4)  dr's of AB(-3 – 0,1 + 2, - 2 -2)

 (a,b,c) = (-3, 3, -4)

Equation of the plane is  -3 ( x – 0 ) +3( y – 1) – 4 (z + 4) = 0

                                  - 3x + 3 y – 4z – 19 = 0

                                   3x - 3y + 4z + 19 = 0

                                  ax + by + cz + d = 0

                                 d > c > a > b

 

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