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Q.

The equation of the straight line bisecting the acute angle between the lines represented by the equation 7x2+6xyy25x+3y2=0 is

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a

2x+6y7=0

b

3xy+1=0

c

2x6y+7=0

d

12x+4y3=0

answer is C.

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Detailed Solution

7x2+6xyy25x+3y27xy+c1x+y+c2

c1+7c2=5 and c1c2=3

c1=2 and c2=1

 The acute angle bisector of the angle between the lines is 7xy+252+x+y12=0

(or) 7xy+2+5(x+y1)=0

i.e., 12x+4y3=0.

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