The equation of the tangent to the circle $x^2 + y^2 + 4x-4y + 4 = 0$ which make equal intercepts on the positive coordinate axes, is

Let the equation of the required tangent be $x + y = a.$ Then,

Length of the perpendicular from centre $=$ Radius

$\Rightarrow \left|\frac{-2+2-a}{\sqrt{2}}\right|=2\Rightarrow a=2\sqrt{2} [\because a>0]$

Hence, the equation of the required tangents is $x+y=2\sqrt{2}$