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Q.

The equation of the tangent to the ellipse 9x2+16y2=144 at the positive end of the latusrectum is

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a

3x+4y=12

b

4x3y=12

c

7x+4y=16

d

3x+7y=16

answer is C.

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Detailed Solution

x216+y29=1ae=7L=ae,b2a=7,94
Tangent is S1=0   xx116+yy19-1=0 7x+4y=16  

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