The equation of trajectory of a projectile is y=10x−59x2. If we assume g = 10 ms–2 the range of projectile (in meters) is

y=10x−59x2When the particle again strikes the ground, y = 0∴10x−59x2=0⇒ x = 0 or 18 mRange = 18 m

The equation of trajectory of a projectile is y=10x−59x2. If we assume g = 10 ms–2 the range of projectile (in meters) is

y=10x−59x2When the particle again strikes the ground, y = 0∴10x−59x2=0⇒ x = 0 or 18 mRange = 18 m

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The equation of trajectory of a projectile is $y = 10 x - (\frac{5}{9}) x^{2}$ . If we assume g = 10 ms^–2 the range of projectile (in meters) is

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$y = 10 x - (\frac{5}{9}) x^{2}$
When the particle again strikes the ground, y = 0
$∴ 10 x - (\frac{5}{9}) x^{2} = 0$
⇒ x = 0 or 18 m

Range = 18 m

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The equation of trajectory of a projectile is y=10x−59x2. If we assume g = 10 ms–2 the range of projectile (in meters) is

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The equation of trajectory of a projectile is $y = 10 x - (\frac{5}{9}) x^{2}$ . If we assume g = 10 ms^–2 the range of projectile (in meters) is