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The equation to one asymptote of the hyperbola $14 x^{2} + 38 x y + 20 y^{2} + x - 7 y - 91 = 0$ is $7 x + 5 y - 3 = 0$ then the other asymptote is

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$2 x + 4 y = 1$

$2 x - 4 y = 1$

$2 x + 4 y + 1 = 0$

$2 x - 4 y + 1 = 0$

answer is C.

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Detailed Solution

Verification : $(7 x + 5 y - 3) (2 x + 4 y + 1) = 0$

$14 x^{2} + 38 x y + 20 y^{2} + x - 7 y - 3 = 0$

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