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The equation to the pair of lines passing through (1,1) and parallel to the pair of lines $3 x^{2} - 3 xy + 4 y^{2} + 3 x - 5 y + 2 = 0$ is

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$x^{2} - 3 xy + 4 y^{2} + 3 x - 5 y + 4 = 0$

$3 x^{2} - 3 xy + 4 y^{2} - 3 x - 5 y + 4 = 0$

$x^{2} - 3 xy + 4 y^{2} + x - 5 y - 2 = 0$

$x^{2} - 3 xy + 4 y^{2} + x - 5 y - 1 = 0$

answer is C.

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Detailed Solution

$3 (x - 1)^{2} + (- 3) (x - 1) (y - 1) + 4 (y - 1)^{2} = 0$

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