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Q.

The equation to the perpendicular bisector of the line segment joining 1,2 and 3,4 is

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a

x+y-5=0

b

3x-2y+5=0

c

x+y-4=0

d

2x-y+5=0

answer is B.

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Detailed Solution

Let the points A1 ,2 and B3 ,4

mid point of AB=1+32 , 2+42=2 , 3

slope of AB =4-23-1=1

slope of perpendicular bisector =-1slope of AB=-11=-1

let m=-1 and 2 ,3 =x1 , y1  Required equation is y-y1=mx-x1 y-3=-1x-2 y-3=-x+2 x+y-5=0

 

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The equation to the perpendicular bisector of the line segment joining 1,2 and 3,4 is