Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6

Q.

The equation whose roots exceed by 2 than the roots of 4x4+32x3+83x2+76x+21=0  is

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away
An Intiative by Sri Chaitanya

a

4x413x29=0

b

4x413x2+9=0

c

4x4+13x2+9=0

d

4x4+12x29=0

answer is B.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

Given roots are exceeded by 2.

α+2=x

α=x2

The equation is 4(x2)4+32(x2)3+83(x2)2+76(x2)+21=0

All x2  terms 32x2+64x2192x2+83x2=13x2

All constant terms 46256+332152+21=9

The equation is 4x413x2+9=0

Watch 3-min video & get full concept clarity

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon