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The equation whose roots are 1 ± 2i, 0, 1 is

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$x (x^{3} + 3 x^{2} - 7 x + 4) = 0$

$x (x^{3} - 3 x^{2} + 7 x - 5) = 0$

$x (x^{3} - 3 x^{2} - 7 x + 4) = 0$

$x (x^{3} - 3 x^{2} + 7 x - 4) = 0$

answer is B.

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Detailed Solution

$α = 0, β = 1, γ = 1 + 2 i, δ = 1 = 1 - 2 i$

$(x - 0) (x - 1) (x^{2} - 2 x + 5) = 0$

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