The equation whose roots are cubes of the roots of x³ + 3x² + 2 = 0 is

$\text{ Let }y=x^3$

$$\begin{gathered} \begin{array}{r}{x}^3+3x^2+2=0\Rightarrow x^3+2=-3x^2\\ \Rightarrow {\left(x^3+2\right)}^3={\left(-3x^2\right)}^3\\ \Rightarrow x^9+8+3x^3\cdot 2\left(x^3+2\right)=-27x^6\\ \Rightarrow x^9+6x^6+12x^3+8=-27x^6\\ \Rightarrow x^9+33x^6+12x^3+8=0\end{array} \\ \text{ Substituting }y=x^3\text{, we get } \\ {y}^3+33y^2+12y+8=0 \\ \text{ Now replacing }y\text{ by }x \\ {x}^3+33x^2+12x+8=0\text{ is the required equation. } \end{gathered}$$