The equation whose roots are multiplied by 3 of those of $2{\mathrm{x}}^3 – 3{\mathrm{x}}^2 + 4\mathrm{x} – 5 = 0$ is

$\begin{array}{l}f\left(x\right)=2x^3-3x^2+4x-5=0\\ \mathrm{Re}quiredEquationisf\left(\frac{x}{3}\right)=0\\ \Rightarrow 2{\left(\frac{x}{3}\right)}^3-3{\left(\frac{x}{3}\right)}^2+4\left(\frac{x}{3}\right)-5=0\\ \Rightarrow 2\left(\frac{x^3}{27}\right)-3\left(\frac{x^2}{9}\right)+\frac{4x}{3}-5=0\\ \Rightarrow 2x^3-9x^2+36x-135=0\end{array}$