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Q.

The equation x33qx+2r=0  has a repeated root then

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a

q3=r2

b

q=r2

c

q3=r

d

q2=r3

answer is D.

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Detailed Solution

f(x)=x33qx+2r=0

f1(x)=3x23q=0

x2(q)2=0

(xq)(x+q)=0

x=q,+q

qq3qq+2r=0

2qq+2r=0

qq=r

Squaring on both sides

q3=r2

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