The equation $x^5-5x^3+5x^2-1=0$ has 3 equal roots. If  $\alpha ,\beta$ are the other two roots of the equation then $\alpha +\beta +\alpha \beta =\_\_\_$

$f\left(x\right)=x^5-5x^3+5x^2-1=0$
$\begin{array}{rl} & f^1\left(x\right)=5x^4-15x^2+10x\\ & f^{11}\left(x\right)=20x^3-30x+10=0\\ & f\left(1\right)=0,f^1\left(1\right)=0,f^{11}\left(1\right)=0\end{array}$
1 is multiple roots

$1,1,1,\alpha ,\beta$ be the roots
$s_1=0s_5=1$
$1+1+1+\alpha +\beta =0\mathrm{1.1.1.}\alpha .\beta =1$
$\alpha +\beta +\alpha \beta =-3+1=-2$