The equation $16{\mathrm{x}}^2-3{\mathrm{y}}^2-32\mathrm{x}-12\mathrm{y}-44=0$ represents a hyperbola with 

Equation of hyperbola is $\frac{(\mathrm{x}-1{)}^2}{3}-\frac{(\mathrm{y}+2{)}^2}{16}=1$, Centre $\mathrm{C}=(1, -2)$, Length of transverse$=2\sqrt{3}$

Length of conjugate = 8