The equations of straight lines whose X-intercept (a), Y-intercept (b) are given by a + b = 5 and ab = 6 are

a and b are the X and Y intercepts respectively.

$\begin{array}{l}\mathrm{a}+\mathrm{b}=5,\mathrm{ab}=6\\ \therefore \mathrm{a}(5-\mathrm{a})-6=0\\ {\mathrm{a}}^2-5\mathrm{a}+6=0\end{array}$

$$\begin{gathered} \mathrm{a}=2 and \mathrm{a}=3 \\ \Rightarrow \mathrm{b}=3 and \mathrm{b}=2 \end{gathered}$$

The equations are $3\mathrm{x}+2\mathrm{y}-6=0$, $2\mathrm{x}+3\mathrm{y}-6=0$