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Q.

The equations of the tangents to the hyperbola 3x2  4y2 = 12 which are parallel to the line 2x + y + 7 = 0 are

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a

3x-y±2=0

b

3x-y±2=0

c

3x-y±6=0

d

2x+y±13=0

answer is A.

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Detailed Solution

x24-y23=1 a2=4, b2=3 slope of given line 2x+y+7=0 is -2

slope of required tangent m=-2

Now Equation of req. tangent is y=mx±a2m2-b2

y=-2x±13 2x+y±13=0

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