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The equations to a pair of opposite sides of a parallelogram are $x^{2} - 5 x + 6 = 0 and y^{2} - 6 y + 5 = 0$ . The equations to its diagonals are

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$x + 4 y = 13, y = 4 x - 7$

$4 x + y = 13, 4 y = x - 7$

$4 x + y = 13, y = 4 x - 7$

$y - 4 x = 13, y + 4 x = 7$

answer is C.

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Detailed Solution

The sides of parallelogram are

$x - 2 = 0, x - 3 = 0, y - 1 = 0, y - 5 = 0$

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